Исходный код вики Command Line Arguments Parser
Редактировал(а) Alexandr Fokin 2023/05/07 13:08
Скрыть последних авторов
| author | version | line-number | content |
|---|---|---|---|
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1.2 | 1 | |commandlineparser/commandline |
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1.1 | 2 | [[https:~~/~~/github.com/commandlineparser/commandline>>https://github.com/commandlineparser/commandline]] |
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1.2 | 3 | [[https:~~/~~/github.com/commandlineparser/commandline/wiki>>https://github.com/commandlineparser/commandline/wiki]]| |
| 4 | |fclp/fluent-command-line-parser | ||
| 5 | [[https:~~/~~/github.com/fclp/fluent-command-line-parser>>https://github.com/fclp/fluent-command-line-parser]]| | ||
| 6 | | | | ||
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1.1 | 7 | |
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1.3 | 8 | ---- |
| 9 | |||
| 10 | ==== Внутренние ссылки: ==== | ||
| 11 | |||
| 12 | ====== Дочерние страницы: ====== | ||
| 13 | |||
| 14 | {{children/}} | ||
| 15 | |||
| 16 | ====== Обратные ссылки: ====== | ||
| 17 | |||
| 18 | {{velocity}} | ||
| 19 | #set ($links = $doc.getBacklinks()) | ||
| 20 | #if ($links.size() > 0) | ||
| 21 | #foreach ($docname in $links) | ||
| 22 | #set ($rdoc = $xwiki.getDocument($docname).getTranslatedDocument()) | ||
| 23 | * [[$escapetool.xml($rdoc.fullName)]] | ||
| 24 | #end | ||
| 25 | #else | ||
| 26 | No back links for this page! | ||
| 27 | #end | ||
| 28 | {{/velocity}} | ||
| 29 | |||
| 30 | ---- |